62Quiz 20 - 2 D O O − 3 D S − O − 460.5 kJ/mol Substituting the numbers gives 1 2 319.7 3 2 D 495 − 3 D S − O − 460.5 kJ/mol Solving

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20 Solution: Wow! we never did one like this before. But if you just write the equation for the enthalpy of reaction you will see that the desired value of D S O is easily found. For the reaction 1 2 S 2 g 3 2 O 2 g SO 3 g Δ H 460.5 kJ/mol The enthalpy of reaction is Δ H 1 2 D S S 3
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Unformatted text preview: 2 D O O − 3 D S − O − 460.5 kJ/mol Substituting the numbers gives 1 2 319.7 3 2 D 495 − 3 D S − O − 460.5 kJ/mol Solving for D S O gives D S − O − 454 kJ/mol...
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This note was uploaded on 11/21/2011 for the course CHEM CHEM 1201 taught by Professor Rupnik during the Spring '11 term at LSU.

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