63Quiz 34 - d. The total pressure will be the sum of the...

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34 Solution: The balanced reaction is P 4 s 6H 2 g 4PH 3 g The amounts of two reactants are given so this is a limiting reagent problem. If hydrogen is in excess and all of the P 4 reacts the amount of product obtained will be m gP 4 4 30.97 g/mol 4 mole PH 3 1 mole P 4 2. 9706 mole PH 3 If P 4 is in excess and all of the H 2 reacts the amount of product obtained will be moles H 2 4 mole PH 3 6 mole H 2 pV RT 4 mole PH 3 6 mole H 2 6. 7753 atm 34.0 L 0.08206 atm L/mol K 300.0 K 4 mole PH 3 6 mole H 2 6. 2383 mole PH 3 a. The smaller amount of product is found when P 4 is the limiting reagent . 2. 9706 mole PH 3 is expected to be produced. b. This tells us that P 4 will be completely used up in the reaction. When the reaction is complete the partial pressure of P 4 0. c. H 2 is in excess so there will be a partial pressure of hydrogen remaining after the reaction is complete.
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Unformatted text preview: d. The total pressure will be the sum of the partial pressures of the hydrogen and the PH 3 . P total P H 2 P PH 3 n H 2 n PH 3 RT V The moles of hydrogen consumed in the reaction can be found from the moles of PH 3 produced. 2. 9706 mole PH 3 6 mole H 2 4 mole PH 3 4. 4559 mole H 2 used Moles of hydrogen left over are initial moles H 2 moles H 2 used mole H 2 left over p H 2 initially V RT mole H 2 used mole H 2 left over 6. 7753 atm 34.0 L 0.08206 atm L/mol K 300.0 K 4. 4559 mole H 2 used 4. 9015 mole H 2 left over Now compute the total pressure P total P H 2 P PH 3 n H 2 n PH 3 RT V 4. 9015 2. 9706 RT V 5. 6999 atm...
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This note was uploaded on 11/21/2011 for the course CHEM CHEM 1201 taught by Professor Rupnik during the Spring '11 term at LSU.

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