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Chem 1201 Test 3 Ch 10

Chem 1201 Test 3 Ch 10 - As a increases pressure will...

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Chem 1201 Test 3 - Ch 10 Page 1 2 Types of R K mol L atm R = 08206 . 0 Use this R in nRT pV = K mol J R = 314 . 8 Use this R in M T R u 3 = Ideal Gas Law Temperature is in Kelvin C K 0 15 . 273 + = nRT pV = RT M g pV = RT pV n = RT pV M g = Boyle’s Law 2 2 1 1 V p V p = Charles Law 2 2 1 1 T V T V = Combined 2 2 2 1 1 1 T V P T V P = (atm) (g/mol) Density T R M P = ρ Units for density is g/L Partial Pressures Total p X p A A = = n n X A A 0 . 1 = + + C B A X X X
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Chem 1201 Effusion and Diffusion Higher temperatures mean Lower formula Mass means Graham’s Law of Effusion 2 2 1 2 1 r M r = Van der Waals Equation nb V T R n p - = Denominator is actual volume available to molecu (Gives higher press As b increases, pressure will increas
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Unformatted text preview: As a increases, pressure will decrea Test 3 - Ch 10 Average Kinetic Ene 2 2 1 mu E k = Root Mean Square Molecule Velocity (m M T R u 3 = R is 8.314 J/(mol·K) Only in this formula is Ex. For H 2 use 2.01588 k ns faster molecules s faster molecules 2 M 2 2 2 1 2 1 t M t M = 2 2 V a n b-2 nd term is attractive force btwn molec (Gives lower real pressures than expec ules sure than expected) se ase Page 2 ergy /s) is M in kg kg in this formula cules cted)...
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Chem 1201 Test 3 Ch 10 - As a increases pressure will...

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