HW_1_Solution - PGE 312 SPRING 2006 Physical and Chemical...

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Unformatted text preview: PGE 312 SPRING 2006 Physical and Chemical Behavior of Petroleum Fluids 1 Homework 1 Solution 1.1 All normal paraffins to 010sz H m m i H H & Ge. HJC—H v I 1 I mafia __ C -H I s H H H u Fmpme H ' t? H H H . H (:«ca c -—H 6 W . , ‘ 1.4 HA ‘ u M'H’C ’C‘C-C—H H l l. 4 H cm ‘ I . . H n H a? “ [1-c-c._¢_c_(lz‘¢ ‘ l t ( l l C. —C_ ~l4 H H' H H H- H, [:17 H u H H 4 (3an u_'c ' 1 . a 2+ a4 if I‘C’C *C’cwcaca—C-H ‘ , H’ H ‘1‘ ‘1 L | i l l [’i 1" l'l “imam t? H H H H AC d u a H H 14 H H l ’1 _C- -C' “d —- (E i i 1 1+ 1+ ‘ i . 'C- ‘C-C —H H 1+ ‘ l l . H’ H H H M 1+ "became H I ‘5. H. Mr [4, R H —c:—c -c_éaé . , [fig 1+ H . | i l _C fl-C' "C. ._C _‘ i4 1+ .4 H ' c , ( (IL—H CUCJ°P€nF=qe Cad“) Mflcqg‘ Y" H’ H- '1‘ 13mm: GLDPQM—Cné 2‘ 4 _ Tammjlficlahcncfll 2’“”me C. i \ H_C C‘H I ll H-—C. /C.-I+ \ C: H a '? iquene “'C‘H“ I C. //v \C—H HvC, ‘ H H_C (3—H / 9 \’\ “,2-” "H Ehjl-Ioenzcné u—C‘ C. 4 \c~“ H—Cl u ..H H’C\ \c A H - "H lemc H (I, c \ f‘ H, C/ C__Cl'¢lr\ é “ ‘* H’ Ca1+ \C/ .4' H '14- » l H \ ‘ (‘- 2J1 1 m J benzene. C / W‘C -C 1+ \C / 1.5 Isomers of Heptane ' n—H‘CFFch ‘5‘ ‘H i+ H__ H i+ H— H—C ' q “ C —' C —— c. - c' ‘ I ~ : —c — A 4+ 1+ H a I; ‘1‘ ‘ . W H 2 LCLGQC H 1 W—C—H H? I ‘l’l’ H H— H H—ch ._ __ ‘ ' a a . C} Ci: -— C — C—H- H Hr Fr ‘ l I+ k+ H 3 ' 55- Math-‘3‘ v- Ckaqc. 14 Hr Hr l '-H 1+ 'C. 2; k? 'H- If (1* I 1 “Ct ‘ C "C —c ——(-|— H H H i“ 1 . M“ 1+ H ‘2: g ‘ Ali" H I {.4 u»q“" 1+ ‘1 1+ l I H ‘? "’ C] - C -— C. .— C ’H H H' i t l u.,C;—H \4’ H“ H 5. 9-. :2 _, . puma—.Lj‘Pefllr-‘né 5‘ Ja— —£* [4- ‘ C l,\_ [4, 14‘ a I I c l H-E—c‘. —<; —c;-—c;—H I i ' | u_c_wl4 H Mr H 1.9 a. Homologous series is a family of chemical compounds whose successive members have a regular difference in composition, especially of the carbon and two hydrogen atoms. Example is Alkanes CnH2n+2 b. Olefin are homologous series known as alkenes or unsaturated hydrocarbons. Example is Ethene CH2=CH2 c. Diolefm are hydrocarbon compounds that contain two double bonds. Example is 1,2-Butadiene CH2=C=CH-CH3 d. Cyclic hydrocarbons have the carbon atoms arranged in a ring structure. Example is Cyclopentane e. Unsaturated hydrocarbon can absorb hydrogen i.e. they have less than the full compliment of hydrogen present in a hydrocarbon chain or ring. Example is Alkenes 1.1 1 a. Paraffin series CnH2n+2 b. Olefin series CnHzn c. Diolefin series CnHZmz d. Acetylene series CnH2n.2 e. Naphthene series CnHzn 1-12 a. 3-Methylhexane will have a higher boiling point than 3-Methylpentane because of larger number of carbon atoms leading to higher intermolecular forces. b. n-Hexane will have a higher boiling point than 3-Methylpentane because the intermolecular forces are less in the later due to branching. c. The boiling point will be higher for n-Pentane due to the presence of double carbon bond in l-Pentene. d. 2-methyl-1-butene (88 F) will have a slightly higher boiling point. Although it is branched but at the same time less symmetric as compared to l-pentene (86 F). 1-14 B'Phemj‘ :4 H /C C \ u- c/ \ / C ‘“ ..——— C I l ‘ H u’C I c; /c ’H \\ /C\ / \\c C H H H CLJWL’M'Lene 'CL /C. H; C’ \C 1H l H Q,C C—H \\ / C l H (J a 01¢ H‘ H C I / \ /c’ \ H‘C C C-—H H‘C C C ~—l+ \C // 0‘ '5u' r—I‘de. ...
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HW_1_Solution - PGE 312 SPRING 2006 Physical and Chemical...

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