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IRWIN 9e 13_55

# IRWIN 9e 13_55 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis. 9/E 1355 The switch in the circuit in Fig. P1355 has; been cinm‘d [111' a Jnng time and i5 ripened at I = CI. Find 3in [111' I D. using Laplace ii'unrn'nrrnh'. i=0 Figure P1355 SOLUTION: 7.0V Chapter 13: The Laplace Transform Problem 13.55 2 Irwin, Basic Engineering Circuit Analysis, 9/E 100 511 1H OCH? Iov Cult) +IO£(t)+ i [400011 : /0 Cu: 00“! 31(3) - my) +10 law; my : Io 0.09 s 3“ 1(3) [s+/o+/ ]:_i_q+3 00%: 5 ICS) [O'OHS +0-q+:<|_ l : 93.814041 Problem 13.55 _ Chapter 13: The Laplace Transform Irwin, Basic Engineering Circuit Analysis, 9/E I0) I [O'Ok—{S1 +O'US+ f] : O'LI‘}O'I?J 5 1(3): (Wm-I2: __§__.,..__.__ ’ Q‘Owﬁnt ousﬂ 5 \ 1(3) = (3°le + 0.4 Jaﬁﬁxng - Sz+lo\$+£5 _ A B ..___ T(§)" 3+5 ‘+ (8+5)z 38+!O’ : A + B 324105+ZS “3 (“L571 35+Io : A(\$+ 5) +8 Let s: —5 305) +10 2 8 B=«5 Lei S30 lo: SAME 5A: ’01'5 A:3 ICS): 3 + -5— H S 345~ (3+5}l ‘ Chapter 13: The Laplace Transform Problem 13.55 ' 4 Irwin, Basic Engineering Circuit Analysis, 9/E - v51? [(1)3(365t ~5te )uctM __—__—.—__—__—__.—__——————————————————- Problem 13.55 Chapter 13: The Laplace Transform ...
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