HW02-solutions

# HW02-solutions - handa(nh5757 HW02 meth(55830 This...

This preview shows pages 1–2. Sign up to view the full content.

handa (nh5757) – HW02 – meth – (55830) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points Determine the value of lim x 2 f ( x ) + 2 g ( x ) 5 f ( x ) 6 g ( x ) when lim x 2 f ( x ) = 3 , lim x 2 g ( x ) = 4 . 1. limit = 5 9 2. limit = 5 39 correct 3. limit = 11 9 4. limit does not exist 5. limit = 11 39 Explanation: By properties of limits lim x 2 f ( x ) + 2 g ( x ) = lim x 2 f ( x ) + 2 lim x 2 g ( x ) = 5 while lim x 2 5 f ( x ) 6 g ( x ) = 5 lim x 2 f ( x ) 6 lim x 2 g ( x ) = 39 negationslash = 0 Consequently, by properties of limits again, lim x 2 f ( x ) + 2 g ( x ) 5 f ( x ) 6 g ( x ) = 5 39 . 002 10.0points Below are the graphs of functions f and g . 4 8 4 4 8 4 8 f : g : Use these graphs to determine lim x 8 { f ( x ) + g ( x ) } . 1. limit = 3 2. limit = 3 3. limit does not exist 4. limit = 7 5. limit = 1 correct Explanation: From the graph it is clear that lim x 8 { f ( x ) + g ( x ) } = 1 .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern