HW03-solutions

HW03-solutions - handa (nh5757) – HW03 – meth –...

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Unformatted text preview: handa (nh5757) – HW03 – meth – (55830) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points If the function f is continuous everywhere and f ( x ) = x 2 − 9 x + 3 when x negationslash = − 3, find the value of f ( − 3). 1. f ( − 3) = 9 2. f ( − 3) = − 6 correct 3. f ( − 3) = 3 4. f ( − 3) = 6 5. f ( − 3) = − 9 6. f ( − 3) = − 3 Explanation: Since f is continuous at x = − 3, f ( − 3) = lim x →- 3 f ( x ) . But, after factorization, x 2 − 9 x + 3 = ( x − 3)( x + 3) x + 3 = x − 3 , whenever x negationslash = − 3. Thus f ( x ) = x − 3 for all x negationslash = − 3. Consequently, f ( − 3) = lim x →- 3 ( x − 3) = − 6 . 002 10.0 points Determine which of the following could be the graph of f near the origin when f ( x ) = x 2 − 7 x + 10 2 − x , x negationslash = 2 , 4 , x = 2 . 1. 2. correct 3. 4. handa (nh5757) – HW03 – meth – (55830) 2 5....
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This note was uploaded on 11/21/2011 for the course M 408N taught by Professor Gualdini during the Spring '10 term at University of Texas.

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HW03-solutions - handa (nh5757) – HW03 – meth –...

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