midterm 01 – RAMSEY, TAYLOR – Due: Sep 21 2006, 4:00 am
1
Version number encoded for clicker entry:
V1:1, V2:1, V3:2, V4:3, V5:1.
Question 1
part 1 of 1
10 points
Convert the volume 7
.
02 in
.
3
to m
3
, recall
ing that 1 in. = 2.54 cm and 100 cm = 1 m.
1.
8
.
79985
×
10

5
m
3
2.
9
.
07843
×
10

5
m
3
3.
9
.
40617
×
10

5
m
3
4.
9
.
78308
×
10

5
m
3
5.
0
.
000100944 m
3
6.
0
.
000104222 m
3
7.
0
.
000107499 m
3
8.
0
.
000111432 m
3
9.
0
.
000115037 m
3
correct
10.
0
.
00011897 m
3
Explanation:
Basic Concept:
Unit Conversion
Solution:
Convert the units from English
units to SI units:
V
= 7
.
02 in
.
3
·
2
.
54 cm
1 in
3
·
1 m
100 cm
3
= 0
.
000115037 m
3
.
Question 2
part 1 of 1
10 points
A train car moves along a long straight
track.
The graph shows the position as a
function of time for this train.
position
time
The graph shows that the train
1.
moves at a constant velocity all of the
time.
2.
slows down during the first part of the
time and speeds up during the last part of the
time.
3.
speeds up during the first part of the time
and slows down during the last part of the
time.
4.
speeds up all the time.
5.
slows down all the time.
correct
Explanation:
The slope of the curve diminishes as time
increases.
Among the choices give, The train “slows
down all of the time” best describes the situ
ation.
Question 3
part 1 of 1
10 points
Assume:
The ball is thrown so that the
man’s muscles give the ball the same speed in
each case. Neglect the height of the man.
A man can throw a ball a maximum hori
zontal distance of 60
.
7 m.
The acceleration of gravity is 9
.
8 m
/
s
2
.
How far can he throw the same ball verti
cally upward?
1.
28
.
45 m
2.
29
.
4 m
3.
30
.
35 m
correct
4.
31
.
3 m
5.
32
.
3 m
6.
33
.
3 m
7.
34
.
35 m
8.
35
.
45 m
9.
36
.
55 m
10.
37
.
7 m
Explanation:
The range of a particle is given by the ex
pression
R
=
v
2
0
sin 2
θ
g
.
The maximum horizontal distance is obtained
when the ball is thrown at an angle
θ
= 45
◦
and sin 2
θ
= 1
.
Solving for
v
0
,
v
0
=
p
g R .
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midterm 01 – RAMSEY, TAYLOR – Due: Sep 21 2006, 4:00 am
2
When the ball is thrown upward with this
speed, the maximum height is obtained from
the equation
v
2
f
=
v
2
0

2
g h .
Let
v
f
= 0, and solve for
h
h
=
R
2
=
v
2
0
2
g
.
Question 4
part 1 of 1
10 points
A cylinder, 18 cm long and 5 cm in radius,
is made of two different metals bonded end
toend to make a single bar. The densities are
4
.
9 g
/
cm
3
and 6
.
5 g
/
cm
3
.
18 cm
5 cm
What length of the lighter metal is needed
if the total mass is 7651 g?
1.
9
.
1522 cm
2.
9
.
45556 cm
3.
9
.
76995 cm
4.
10
.
0838 cm
5.
10
.
4003 cm
6.
10
.
7222 cm
7.
11
.
0658 cm
8.
11
.
437 cm
9.
11
.
8415 cm
10.
12
.
2403 cm
correct
Explanation:
Let :
‘
= 18 cm
,
r
= 5 cm
,
ρ
1
= 4
.
9 g
/
cm
3
,
ρ
2
= 6
.
5 g
/
cm
3
,
and
m
= 7651 g
.
Volume of a bar of radius
r
and length
‘
is
V
=
π r
2
‘
and its density is
ρ
=
m
V
=
m
π r
2
‘
so that
m
=
ρ π r
2
‘
‘
x
‘

x
r
Let
x
be the length of the lighter metal;
then
‘

x
is the length of the heavier metal.
Thus,
m
=
m
1
+
m
2
=
ρ
1
π r
2
x
+
ρ
2
π r
2
(
‘

x
)
=
ρ
1
π r
2
x
+
ρ
2
π r
2
‘

ρ
2
π r
2
x .
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 Spring '08
 Turner
 Physics, Acceleration, Orders of magnitude, m/s, Skating

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