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Unformatted text preview: An example We can use the ray diagram above to do an example. If the focal length of the diverging lens is 12.0 cm (f is always negative for a diverging lens), and the object is 22.0 cm from the lens and 5.0 cm tall, where is the image and how tall is it? Working out the image distance using the lens equation gives: This can be rearranged to: The negative sign signifies that the image is virtual, and on the same side of the lens as the object. This is consistent with the ray diagram. The magnification of the lens for this object distance is: So the image has a height of 5 x 0.35 = 1.75 cm....
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This note was uploaded on 11/22/2011 for the course PHY PHY2053 taught by Professor Davidjudd during the Fall '10 term at Broward College.
 Fall '10
 DavidJudd
 Physics

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