Math 10 Exam 1 Sample Questions with solution.pdf - 0DWK\u000310 Exam 1\u00033UDFWLFH\u00033UREOHPV\u0003%ULQJ\u0003WR\u0003WKH\u0003H[DP\u001d\u0003 \u0014 VKDUS\u0003SHQFLOV\u000f\u0003JRRG\u0003HUDVHU\u000f\u0003FDOFXODWRU \u0015

Math 10 Exam 1 Sample Questions with solution.pdf -...

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0DWK 10 Exam 1 3UDFWLFH 3UREOHPV %ULQJ WR WKH H[DP± ²³ VKDUS SHQFLOV´ JRRG HUDVHU´ FDOFXODWRU µ³ Two VLGH s RI RQH ¶·¸´ î ²²´ VKHHW RI IRUPXODV ¹QR VSHFLILF H[DPSOHV³ 1.Using the frequency distribution, find the midpoint, relative frequency, and cumulativefrequency of each class. Describe any patterns. Solution The midpoints, relative frequencies, and cumulative frequencies of the first three classes are calculated as follows. Class f Midpoint Relative frequency Cumulative frequency 65 –104 6 65 + 104 2 = 84.5 6 30 = 0.2 6 105 –144 9 105 + 144 2 = 124.5 9 30 = 0.3 6 + 9 = 15 145 –184 6 145 + 184 2 = 164.5 6 30 = 0.2 15 + 6 = 21 The remaining midpoints, relative frequencies, and cumulative frequencies are shown in the expanded frequency distribution. Frequency Distribution for Prices (in dollars) of GPS Navigators Class Frequency, f Midpoint Relative frequency Cumulative frequency 65 –104 6 84.5 0.2 6 105 –144 9 124.5 0.3 15 145 –184 6 164.5 0.2 21 185 –224 4 204.5 0.13 25 225 –264 2 244.5 0.07 27 265 –304 1 284.5 0.03 28 305 –344 2 324.5 0.07 30 Σ f = 30 Σ f n 1 Prices Number of GPS navigators Portion of GPS navigators 128 100 180 150 200 90 340 105 85 270 200 65 230 150 150 120 130 80 230 200 110 126 170 132 140 112 90 340 170 190