# Caesar - kg/m s 2(5.10 x 10 14 m 2 Force = 5.15 x 10 19 kg...

This preview shows pages 1–2. Sign up to view the full content.

Caesar's Las Breath Of the molecules in Caesar's last gasp, how many of them are in the breath you just took? Given: One breath= 2 liters of air at a pressure of 730 mmHg and 37 degrees Celsius. Earth is a sphere with a radius of 6370 Km and an average barometric pressure of 760mm Hg. (D of Hg=13.6g/cm 3 ) The avg. molecular mass of air is 29 g/mol. 1. Number of moles in Caesar’s last breathe: n = PV/RT = (0.96 atm)(2L)/(0.0821 L atm/mol K)(310 K) n = 0.075 mol 2. Number of moles in the atmosphere: a. Surface area of earth: Area = (4)( π )(r 2 ) Area = 5.10 x 10 14 square meters b. Pressure of the atmosphere on the earth’s surface: Pressure = 760 mm Hg = 1.01 x 10 5 Pascals = 1.01 x 10 5 Newtons/square meter Pressure = 1.01 x 10 5 kg/m s 2 c. Force of the atmosphere on the earth Pressure = Force/Area Therefore Force = (Pressure)(Area) Force = (1.01 x 10 5

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: kg/m s 2 )(5.10 x 10 14 m 2 ) Force = 5.15 x 10 19 kg m /s 2 d. Mass of the atmosphere Force = (mass)(acceleration) therefore mass = Force/acceleration mass = (5.15 x 10 19 kg m/s 2 )/(9.8 m/s 2 ) note: this is the acceleration due to gravity mass = 5.26 x 10 18 kg or 5.26 x 10 21 g e. Moles in the atmosphere mol = (5.26 x 10 21 g)(1 mol/29 g) mol = 1.81 x 10 20 mol 3. Fraction of atmosphere which represents molecules from Caesar’s last breath: (0.075 mol)/(1.81 x 10 20 mol) = 4.14 x 10-22 4. Moles of Caesar’s last breath in your last breath: Assume your breath holds 0.075 mol: (0.075 mol)(4.14 x 10-22 ) = 3.11 x 10-23 mol 5. Number of molecules: (6.022 x 10 23 molecules/mol)(3.11 x 10-23 mol) = 18.7 molecules ( An even more disconcerting fact is that he probably had flatulence as well. )...
View Full Document

## This note was uploaded on 11/22/2011 for the course CHEMISTRY CHM1025 taught by Professor Laurachoudry during the Fall '10 term at Broward College.

### Page1 / 2

Caesar - kg/m s 2(5.10 x 10 14 m 2 Force = 5.15 x 10 19 kg...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online