Unformatted text preview: so, 1.5 moles of CaCl2 would be: (1.5 mole )(110.984 grams/mole ) = 166.476 grams "Igor! I have 2.8 grams of gold, how many atoms do I have?" Molecular formula of gold is: Au Molecular weight of Au = 196.9665 amu Therefore, 1 mole of gold weighs 196.9665 grams. So, in 2.8 grams of gold we would have: (2.8 gram )(1 mole/196.9665 gram ) = 0.0142 mole From Avogadro's number, we know that there are approximately 6.02 x 10 23 atoms/mole. Therefore, in 0.0142 moles we would have: (0.0142 mole )(6.02 x 10 23 atoms/mole ) = 8.56 x 10 21 atoms...
View
Full
Document
This note was uploaded on 11/22/2011 for the course CHEMISTRY CHM1025 taught by Professor Laurachoudry during the Fall '10 term at Broward College.
 Fall '10
 LauraChoudry
 Chemistry, Mole

Click to edit the document details