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Lecture_6_Dimensional_Analysis (1)

Lecture_6_Dimensional_Analysis (1) - LECTURE NOTES LECTURE...

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L E C T U R E N O T E S LECTURE 6 Dimensional Analysis (5.6) GENERAL CHEMISTRY Fall 2009 Updated: 11/22/2011
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5.6 Dimensional Analysis I.  Dimensional Analysis  (also known as “factor-labeling”) A. An approach to solving problems a. Think of ratios (e.g., cow example) i. 1 cow makes 3 moos; therefore, 3 cows make how many moos?  The ratio 1 cow / 3 moos is important. B. Converting between units a. One step b. Two step C. Basics Yesterday we showed that there are 2 parts to a problem, the numbers and the  units.  112.07 g  ÷  9.2 mL = 12.181521739 g/mL   We round the answer to 12 g/mL because 9.2 mL has 2 significant figures. The  sig. fig. rule to remember is that in multiplication and division the answer is  rounded to the least significant figure from the variable terms. (1) Do the math on your calculator (2) Do the units a. Never forget the units. We do not say someone is “6 tall” but “6 –
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Lecture_6_Dimensional_Analysis (1) - LECTURE NOTES LECTURE...

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