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Unformatted text preview: First we compute the number of moles of NH 3 (M.W. = 17.031 g/mole) and the number of moles of CuO (M.W. = 79.5 g/mole). To determine which reagent is limiting we use the mole ratio from the chemical equation to convert moles NH 3 to moles CuO. So, only 1.14 moles of CuO is available, therefore CuO is the limiting reagent. That is, CuOwill run out before the NH 3 does. The mass of N 2 produced will be...
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- Fall '10
- Chemistry, NH3, moles NH3, solid copper, 1.14 moles, 17.031 g