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Unformatted text preview: First we compute the number of moles of NH 3 (M.W. = 17.031 g/mole) and the number of moles of CuO (M.W. = 79.5 g/mole). To determine which reagent is limiting we use the mole ratio from the chemical equation to convert moles NH 3 to moles CuO. So, only 1.14 moles of CuO is available, therefore CuO is the limiting reagent. That is, CuOwill run out before the NH 3 does. The mass of N 2 produced will be...
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This note was uploaded on 11/22/2011 for the course CHEMISTRY CHM1025 taught by Professor Laurachoudry during the Fall '10 term at Broward College.
- Fall '10