Quantum Effects and Photons

# Quantum Effects and Photons - Calculate the smallest amount...

This preview shows page 1. Sign up to view the full content.

Quantum Effects and Photons What's the difference between a "red hot" poker and a "white hot" poker? The pokers are different temperatures ("white hot" poker has a higher temperature) The pokers emit different intensities and wavelengths of electromagnetic radiation (especially in the visible spectrum Max Planck (1900) Energy can be released (or absorbed) by atoms only in "packets" of some minimum size This minimum energy packet is called a quantum The energy ( E ) of a quantum is related to its frequency ( ν ) by some constant ( h ): E = h ν h is known as " Planck's constant ", and has a value of 6.63 x 10 -34 Joule seconds (Js) Electromagnetic energy is always emitted or absorbed in whole number multiples of (h*
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ) Calculate the smallest amount of energy (i.e. one quantum) that an object can absorb from yellow light with a wavelength of 589 nm Energy quantum = h ν so we need to know the frequency ν ν λ = c ν€ = c/ λ ν€ = (3.00 x 10 8 m/s)/(589 x 10-9 m) ν€ = 5.09 x 10 14 s-1 plugging into Planck's equation: E = (6.63 x 10-34 Js)*( 5.09 x 10 14 s-1 ) E (1 quanta) = 3.37 x 10-19 J Note that a quanta is quite small. When we receive infrared radiation from a fireplace we absorb it in quanta according to Planck's Law. However, we can't detect that the energy absorbtion is incremental. On the atomic scale, however, the quantum effects have a profound influence...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online