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Unformatted text preview: oxygen gas in 22.41 L at 0.0°C V = 22.41 L T = (0.0 + 273) = 273°K a (O 2 ) = 1.36 L 2 atm/mol 2 b (O 2 ) = 0.0318 L /mol P = 117 atm- 27.1 atm P = 90 atm • The pressure will be 90 atm, whereas if it was an ideal gas, the pressure would be 100 atm • The 90 atm represents the pressure correction due to the molecular volume. In other words the volume is somewhat less than 22.41 L due to the molecular volume. Therefore the molecules must collide a bit more frequently with the walls of the container, thus the pressure must be slightly higher. The -27.1 atm represents the effects of the molecular attraction. The pressure is reduced due to this attraction....
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- Fall '10
- Chemistry, Van der Waals, L2 atm/mol2