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Unformatted text preview: oxygen gas in 22.41 L at 0.0C V = 22.41 L T = (0.0 + 273) = 273K a (O 2 ) = 1.36 L 2 atm/mol 2 b (O 2 ) = 0.0318 L /mol P = 117 atm- 27.1 atm P = 90 atm The pressure will be 90 atm, whereas if it was an ideal gas, the pressure would be 100 atm The 90 atm represents the pressure correction due to the molecular volume. In other words the volume is somewhat less than 22.41 L due to the molecular volume. Therefore the molecules must collide a bit more frequently with the walls of the container, thus the pressure must be slightly higher. The -27.1 atm represents the effects of the molecular attraction. The pressure is reduced due to this attraction....
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This note was uploaded on 11/22/2011 for the course CHEMISTRY CHM1025 taught by Professor Laurachoudry during the Fall '10 term at Broward College.
- Fall '10