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**Unformatted text preview: **C. Calculate the rate of formation of ice (in centimeters per hour) on the bottom surface of the ice slab. Take the thermal conductivity of ice to be 0.0040 cal/s . cm . C and the density to be 0.92 g/cm3. The water at the boundary between the water and the ice will be at a temperature of 0 C. The heat transported through 5 cm of ice is equal to This heat is released when water is transformed into ice. The heat of transformation of this process is 79.5 cal/g. Suppose a mass m of water is transformed each second into ice. This produces a total heat equal to H = 79.5 m cal/s This must be equal to the heat flow through the ice: 79.5 m = 0.0080 A A mass m of ice (covering an area A) will have a thickness d, where d is given by Combining the last two expression we obtain for the rate of ice formation:...

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