STAT1051_lesson7(1)

STAT1051_lesson7(1) - A Complete Example The dataset gives...

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Unformatted text preview: A Complete Example The dataset gives ammonia level near an exit ramp of a tunnel tunnel for 8 different days {1.53, 1.50, 1.37, 1.51, 1.55, 1.42, 1.41, 1.48} Mean and SD Obs 1.53 2 Deviation Deviation2 .05875 .00345 1.50 1.37 .02875 .00083 x = 1.47125 -.10125 .01025 Deviation = obs-mean 1.51 1.55 .03875 .001502 .07875 .0062 1.42 1.41 -.05125 .00263 -.06125 .00375 1.48 11.77 .00875 .000077 0 .0286875 .0286875 s= 8 −1 = .004098 2 s = .004098 = .064 Quartiles The Dataset: {1.53,1.50,1.37,1.51,1.55,1.42, 1.41,1.48} Arrange: 1.37,1.41,1.42,1.48,1.50,1.51,1.53,1.55 Q1 Q2 Q3 Median: n=8, avg of the 4th and 5th obs. M = 1.49, QL = 1.415, QU = 1.52 Box Plot Five Number Summary: Min = 1.37 Max =1.55 Q1 = 1.415 M = 1.49 Q3= 1.52 IQR = Q3 – Q1 = QU - QL = 0.105. Box Plot Inner Fence: Lower = 1.415 – (1.5)*.105 = 1.2575 Upper = 1.52 + (1.5)*.105 = 1.6775 All observations are within inner fence; No outlier. SPSS can be used to get box plot as well. min=1.37, Q1=1.415, Q2=1.490, Q3=1.520, max=1.550 Box Plot 1.49 1.37 1.415 1.52 1.55 Remark : There is no outlier. Distribution is skewed to the left ...
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This note was uploaded on 11/27/2011 for the course STAT 1051-10 taught by Professor Balaji during the Fall '11 term at GWU.

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STAT1051_lesson7(1) - A Complete Example The dataset gives...

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