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problem29_52 - 29.52 a The flux through the coil is given...

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29.52: a) The flux through the coil is given by ), cos( t NBA ϖ where N is the number of turns, B is the strength of the Earth’s magnetic field, and is the angular velocity of the rotating coil. Thus, ), sin( t NBA ε = which has a peak amplitude of . 0 NBA = Solving for A we obtain 2 5 0 m 18 T) 10 (8.0 turns) (2000 rev)
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