# Physics II Lab w answers_Part_19 - 49 The integral I...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 49 The integral I = & & L x ) x ( B x d x d can be evaluated to give, [ ] 2 2 2 m d L d d B I- + =------------------------------- (15) I.5. Determination of B m : The value of B m is determined from the period of oscillation of the magnetometer needle. The magnetometer is placed at the center in place of CRT so that the magnets are at a distance of d from it (see fig4). The magnetometer needle aligns itself along the resultant magnetic field fig 4 2 m 2 E B B B + = where B E is the earth’s magnetic field acting towards south . A small disturbance of the needle about the equilibrium position causes it to oscillate. The angular frequency of small oscillations can be easily shown to be (Exercise 7) I B μ ω = , where & is the magnetic moment of the needle and I it’s moment of inertia, and hence the time period of small oscillations B I 2 T μ π = . Now, the resultant magnetic field m 2 m 2 E sin / B B B B θ = + = . Thus 2 2 m T Sin I 4 B θ μ π = In the absence of the magnets B=B...
View Full Document

## This note was uploaded on 11/26/2011 for the course PHY 2053 taught by Professor Lind during the Fall '09 term at FSU.

### Page1 / 2

Physics II Lab w answers_Part_19 - 49 The integral I...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online