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Physics II Lab w answers_Part_53

Physics II Lab w answers_Part_53 - I = I rs e qV kT 1 I...

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117 ) ( I e I I op kT qV rs 3 1 - ° ± ° ² ³ ° ´ ° µ - · · ¸ ¹ º º » ¼ = Following eq.(2), when the device is short circuited (V=0), there is a short – circuit current from p to n equal to I op . The usual (i.e., under dark conditions) V-I characteristic for diode is shown in Fig. 4 by the dashed line that passes through the origin (see eq. (1)). Figure 4. V-I characteristic curves of a photo-diode under dark (------) and illuminated ( ___ ) conditions. When the optical generation current, I op is introduced , the nature of the characteristic curve is modified. In the illuminated condition, the curve passes through the fourth quadrant also. When the circuit is open, I=0, using applied reverse bias is also zero, the potential across the junction due to optical generation of electron – hole pairs, become V oc ( as like V) and one can write from eq. (2), ( ) ) ( n L p L g L L ln q kT V p n n n p p op n p oc 4 1 ½ ½ ½ ½ ½ ½ ¾ ¿ À À À À À À Á Â + ° ± ° ² ³ ° ´ ° µ · · ¸ ¹ º º » ¼ + · · ¸ ¹ º º » ¼ + ·
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