Physics II Lab w answers_Part_62

# Physics II Lab w answers_Part_62 - 10 Fig 3 sin cos t(14...

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135 10) Fig 3 ) t cos( sin A E 1 β - ω β β = ------------------------------------ (14) Similarly, the secondary slit will produce a field ) t cos( sin A E 1 2 Φ - β - ω β β = ------------------------------ (15) at the point P, where θ λ π = Φ sin d 2 1 represents the phase difference between the disturbances from two corresponding points on the slits; by corresponding points we imply pair of points like (A 1 ,B 1 ), (A 2 ,B 2 )… … ., which are separated by a distance d. Hence the resultant field will be [ ] ) t cos( ) t cos( sin A E E E 1 2 1 Φ - β - ω + β - ω β β = + = which represents the interference of two waves each of amplitude β β sin A and differing in phase by 1 . Above equation can be written as ) 2 t cos( cos sin A E 1 Φ - β - ω γ β β = where ± = θ λ π = Φ sin d 2 1 . The intensity distribution will be of the form γ β β = 2 2 2 0 cos sin I 4 I ----------------------------------- (16)

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136 where 2 2 0 sin I β β represents the intensity distribution produced by one of the slits. As
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Physics II Lab w answers_Part_62 - 10 Fig 3 sin cos t(14...

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