# Physics II Lab w answers_Part_66 - the distance X of the...

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143 Table 2: Double Slit diffraction S.No Position of photocell (mm) Main Scale + Vernier = Net Current μ A 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

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144 Calculations & Results: 1. Determination of width od single slit ‘a’ Plot a graph of current Vs position of the photocell. Using data from Table1. Measure the distance x from center of diffraction pattern to the first minimum of the graph paper. Calculate the slit width ‘a’ using (m=1 in eq. 12). λ θ = + = 2 2 sin D X X a a 2. Determination of a & d for double slit Plot a graph of current Vs position of the photocell using data of Table 2. Measuer
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Unformatted text preview: the distance X of the first minimum of the diffraction envelope from the center of the diffraction pattern ( see Fig 4). Measure also the distance y between two consecutive minima of the interface pattern with the diffraction envelope (see Fig 4). Calculate a and d using the following relations. ) 17 . 1 ( 2 4 2 ) 12 . 1 ( 2 2 2 2 eq in n y D y d eq in m D X aX = = + & ± ² ³ ´ µ = = + Results 1. The width of the single slit = ___________________________ mm. 2. For the double slit a = ________________________________ mm. b = ________________________________ mm. (Two graph papers required)....
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## This note was uploaded on 11/26/2011 for the course PHY 2053 taught by Professor Lind during the Fall '09 term at FSU.

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Physics II Lab w answers_Part_66 - the distance X of the...

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