This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: P v v v v v T = RT 1 v 2 , (2.2) = P v . (2.3) The slope of the isentrope is found in the following way. Consider rst the Gibbs equation, Eq. (1.1): Tds = du + Pdv. (2.4) 17 18 CHAPTER 2. CYCLE ANALYSIS v P T s 1 2 3 4 1 2 3 4 w cycle = P dv = q cycle = T ds isentrope isotherm isotherm i s e n t r o p h m is Figure 2.1: Sketch of P v and T s planes for a CPIG in a Carnot cycle. Because the gas is calorically perfect, one has du = c v dT, (2.5) so the Gibbs equation, Eq. (2.4), becomes Tds = c v dT + Pdv. (2.6) Now for the ideal gas, one has Pv = RT, (2.7) Pdv + vdP = RdT, (2.8) Pdv + vdP R = dT. (2.9) CC BYNCND. 18 November 2011, J. M. Powers....
View Full
Document
 Fall '11
 ParkSou
 Dynamics

Click to edit the document details