Thermodynamics filled in class notes_Part_6

19245 kg k 3 178955 10 kp a 1200 k 400 k m3 kg m3 kg

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: v3 v4 1 k −1 = m3 0.19245 kg k 3 = (1.78955 × 10 kP a) 1200 K 400 K m3 kg m3 kg 0.19245 3.000 1 1.4−1 = 3.000 m3 . kg (2.29) 1.4 = 3.82667 × 101 kP a. (2.30) Check: P4 = kJ 0.287 kg K (400 K ) RT4 = 3.82667 × 101 kP a. = 3 v4 3.000 m kg (2.31) A summary of the states is given in Table 2.1. Now calculate the work, heat transfer and efficiency. Take the adiabatic exponent for air to be k = 1.4. Now since cP , cP − cv = R, (2.32) k= cv CC BY-NC-ND. 18 November 2011, J. M. Powers....
View Full Document

Ask a homework question - tutors are online