Thermodynamics filled in class notes_Part_7

Thermodynamics filled in class notes_Part_7 - 2.1 CARNOT 21...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2.1. CARNOT 21 T ( K ) P ( kPa ) v ( m 3 kg ) 1 400 1 . 148 × 10 2 1 . 000 2 1200 5 . 36886 × 10 3 . 06415 3 1200 1 . 78955 × 10 3 . 19245 4 400 3 . 82667 × 10 2 3 . 000 Table 2.1: State properties for Carnot cycle. one gets k = R + c v c v , (2.33) kc v = R + c v , (2.34) c v ( k − 1) = R, (2.35) c v = R k − 1 = . 287 kJ kg K 1 . 4 − 1 = 0 . 7175 kJ kg K . (2.36) Recall the first law: u 2 − u 1 = 1 q 2 − 1 w 2 . (2.37) Recall also the caloric equation of state for a CPIG: u 2 − u 1 = c v ( T 2 − T 1 ) . (2.38) Now process 1 → 2 is isentropic, so it is also adiabatic, hence 1 q 2 = 0, so one has u 2 − u 1 = 1 q 2 bracehtipupleftbracehtipdownrightbracehtipdownleftbracehtipupright =0 − 1 w 2 , (2.39) c v ( T 2 − T 1 ) = − 1 w 2 , (2.40) parenleftbigg . 7175 kJ kg K parenrightbigg (1200 K − 400 K ) = − 1 w 2 , (2.41) 1 w 2 = − 5 . 7400 × 10 2 kJ kg . (2.42) The work is negative as work is being done on the system in the compression process....
View Full Document

{[ snackBarMessage ]}

Page1 / 2

Thermodynamics filled in class notes_Part_7 - 2.1 CARNOT 21...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online