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Unformatted text preview: 2.5. BRAYTON 47 If we have a CPIG, then reg = T x T 2 T x T 2 . (2.277) Example 2.7 (extension for Moran and Shapiro, Example 9.6) How would the addition of a regenerator affect the thermal efficiency of the isentropic version of the previous example problem? One may take the rash step of trusting the analysis to give a prediction from Eq. (2.275) of = 1 T 1 T 3 parenleftbigg P 2 P 1 parenrightbigg ( k 1) /k , (2.278) = 1 parenleftbigg 300 K 1400 K parenrightbigg (10) (1 . 4 1) / 1 . 4 = . 586279 . (2.279) Without regeneration, the thermal efficiency of the ideal Brayton cycle had a value of 0 . 482053. Had the engine used a Carnot cycle between the same temperature limits, the efficiency would have been . 785714. 2.5.3 Ericsson Cycle If one used isothermal compression and expansion, which is slow and impractical, in place of isentropic processes in the Brayton cycle, one would obtain the Ericsson cycle . Diagrams for P v and T s for the Ericsson cycle are shown in Figure 2.12.for the Ericsson cycle are shown in Figure 2....
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This note was uploaded on 11/26/2011 for the course EGN 3381 taught by Professor Parksou during the Fall '11 term at FSU.
 Fall '11
 ParkSou
 Dynamics

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