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Unformatted text preview: 4.11. EQUILIBRIUM IN A TWO-COMPONENT SYSTEM 147 18.104.22.168 Isothermal, isobaric system Allowing for isobaric rather than isochoric equilibration introduces small variation in the analysis. Example 4.15 Consider the same reaction N 2 + N 2 ⇌ 2 N + N 2 . (4.491) for an isobaric and isothermal process. That is, consider 1 kmole of N 2 and 0 kmole of N at a pressure of 100 kPa and a temperature of 6000 K . Using the ideal gas tables, find the equilibrium concentrations of N and N 2 if the equilibration process is isothermal and isobaric. The initial volume is the same as from the previous example: V 1 = 498 . 84 m 3 . (4.492) Note the volume will change in this isobaric process. Initially, the mixture is all N 2 , so its partial pressure is the total pressure, and the initial partial pressure of N is 0. A few other key results are identical to the previous example: n N = 2 ( n N 2 | t =0 − n N 2 ) , (4.493) and 2 g N ≤ g N 2 . (4.494) Substituting using the definitions of Gibbs free energy, one gets...
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This note was uploaded on 11/26/2011 for the course EGN 3381 taught by Professor Park-sou during the Fall '11 term at FSU.
- Fall '11