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Unformatted text preview: 5.2. STOICHIOMETRY 155 Again, this amounts to saying the solution vector ( 1 , 2 , 3 ) T lies in the right null space of the coefficient matrix li . Here is any real scalar. If one takes = 2, one gets 1 2 3 = 2 1 2 , (5.36) This simply corresponds to 2 H 2 O 2 + 2 H 2 O = 0 . (5.37) If one takes = 4, one still achieves stoichiometric balance, with 1 2 3 = 4 2 4 , (5.38) which corresponds to the equally valid 4 H 2 + 2 O 2 4 H 2 O = 0 . (5.39) In summary, the stoichiometric coefficients are nonunique but partially constrained by mass conserva tion . Which set is chosen is to some extent arbitrary, and often based on traditional conventions from chemistry. But others are equally valid. There is a small issue with units here, which will be seen to be difficult to reconcile....
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This note was uploaded on 11/26/2011 for the course EGN 3381 taught by Professor Parksou during the Fall '11 term at FSU.
 Fall '11
 ParkSou
 Dynamics

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