Thermodynamics filled in class notes_Part_76

Thermodynamics filled in class notes_Part_76 - 5.2....

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Unformatted text preview: 5.2. STOICHIOMETRY 159 Dividing the first row by 3, the second by 2 and the third by 8 / 3 gives 1 1 3 1 3 1 1 1 2 1 2 1 2 1 1 3 4 3 8 1 2 3 4 5 6 = . (5.85) Take bound variables to be 1 , 2 , and 3 and free variables to be 4 , 5 , and 6 . So set 4 = 1 , 5 = 2 , and 6 = 3 , and get 1 0 1 3 0 1 1 0 0 1 1 2 3 = 1 3 1 2 2 2 3 2 1 + 3 4 2 + 3 8 3 . (5.86) Solving, one finds 1 2 3 = 1 8 ( 2 2 3 ) 1 8 (4 1 10 2 7 3 ) 1 8 ( 8 1 + 6 2 + 3 3 ) . (5.87) For all the coefficients, one then has 1 2 3 4 5 6 = 1 8 ( 2 2 3 ) 1 8 (4 1 10 2 7 3 ) 1 8 ( 8 1 + 6 2 + 3 3 ) 1 2 3 = 1 8 4 8 8...
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Thermodynamics filled in class notes_Part_76 - 5.2....

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