Thermodynamics filled in class notes_Part_91

Thermodynamics filled in class notes_Part_91 - 5.5 CHEMICAL...

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Unformatted text preview: 5.5. CHEMICAL KINETICS OF A SINGLE ISOTHERMAL REACTION 189 For this problem, T = 6000 K , so k (6000) = 7 . × 10 18 6000 1 . 6 exp parenleftbigg − 1 . 1325 × 10 5 6000 parenrightbigg , (5.375) = 40130 . 2 m 3 kmole s . (5.376) The equilibrium constant K c is also unchanged from the previous example. Recall K c = parenleftbigg P o RT parenrightbigg P N i =1 ν i exp parenleftbigg − Δ G o RT parenrightbigg . (5.377) For this system, since ∑ N i =1 ν i = Δ n = 1, this reduces to K c = parenleftbigg P o RT parenrightbigg exp parenleftbigg − (2 g o N − g o N 2 ) RT parenrightbigg , (5.378) = parenleftbigg P o RT parenrightbigg exp parenleftbigg − (2 g o N − g o N 2 ) RT parenrightbigg , (5.379) = parenleftbigg P o RT parenrightbigg exp parenleftBigg − (2( h o N − Ts o T,N ) − ( h o N 2 − Ts o T,N 2 )) RT parenrightBigg , (5.380) = parenleftbigg 100 (8 . 314)(6000) parenrightbigg exp parenleftbigg − (2(597270 − (6000)216 . 926) − (205848 − (6000)292 . 984)) (8 . 314)(6000) parenrightbigg...
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This note was uploaded on 11/26/2011 for the course EGN 3381 taught by Professor Park-sou during the Fall '11 term at FSU.

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Thermodynamics filled in class notes_Part_91 - 5.5 CHEMICAL...

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