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Unformatted text preview: 7.1. ISOTHERMAL, ISOCHORIC KINETICS 239 We notice that e M cancels. This so-called third body will in fact never affect the equilib- rium state. It will however influence the dynamics. Removing e M and slightly rearranging Eqs. (7.74-7.75) gives a 13 T 13 exp parenleftbigg E 13 RT parenrightbigg e O e O = a 14 T 14 exp parenleftbigg E 14 RT parenrightbigg e O 2 , (7.76) a 13 T 13 exp parenleftbigg E 13 RT parenrightbigg e O e O = a 14 T 14 exp parenleftbigg E 14 RT parenrightbigg e O 2 . (7.77) These are the same equations! So we really have two unknowns for the equilibrium state e O and e O 2 but seemingly only one equation. Note that rearranging either Eq. (7.76) or (7.77) gives the result e O e O e O 2 = a 14 T 14 exp parenleftBig E 14 RT parenrightBig a 13 T 13 exp parenleftBig E 13 RT parenrightBig = K ( T ) . (7.78) That is, for the net reaction (excluding the inert third body), O 2 O + O , at equilibrium the product of the concentrations of the products divided by the product of the concentrations of the reactants is a function of temperature...
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- Fall '11