# came4pt8 - Question.4.8 A simply supported nonmetallic beam...

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A simply supported nonmetallic beam of 0.25 m height, 0.1 m –width, and 1.5 m span is subjected to a uniform loading of 6KN/m. Determine the factor of safety for this loading according to (a)the maximum distortion energy theory, and (b)the maximum shearing stress theory. Use MPa 28 = s yp . Solution: This beam is being subjected to two different types of stresses: bending and shear The bending stress for a beam subjected to a bending moment "M", and moment of inertia "I" is: I My b = s Where, M= bending moment y= distance of the fiber form the neutral axis I = moment of inertia The bending moment at any cross-section distance "x" from the left end is, 2 ) 2 )( . ( 2 x x x M w w = = where, w is load per unit length of the beam. And, the moment of inertia of the cross-section is: 12 3 h b I = Where b= width of the beam h= height of the beam 12 . 2 3 2 h b y x b w s = …………………….(1) Now, we evaluate the shear stress on the cross-section, A sf = t Here, "sf" is the shear force , and “A” is cross-sectional area. h

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came4pt8 - Question.4.8 A simply supported nonmetallic beam...

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