Came8pt30 - Q.8.30 Consider a steel rotating disk of hyperbolic cross-section with a = 0.125m b = 0.625 m t i = 0.125m t o = 0.0625m Determine the

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Q.8.30 Consider a steel rotating disk of hyperbolic cross-section with a = 0.125m, b = 0.625 m, , 125 . 0 m t i = . 0625 . 0 m t o = Determine the maximum tangential force that can occur at the outer surface in newtons per meter of circumference if the maximum stress at the bore is not to exceed 140 MPa. Assume that outer and inner edges are free of pressure. Solution: We start by writing the profile equation for the hyperbolic cross-section of the disk; r t t s - × = 1 Now, since we are given the values of the thickness at the inner and outer radii, we solve the following two equations simultaneously for getting s and t 1 ) 125 . 0 ( 125 . 0 1 s t - × = and, ) 625 . 0 ( 0625 . 0 1 s t - × = to get: 0.4306 s and 05104 . 0 1 = = t We will use this value of “s” to solve the auxiliary equation to get values of m m 2 1 , 0 ) . 1 ( 2 = + - + s sm m n which has the roots: + + ± - = ) . 1 ( 2 2 2 2 / 1 2 , 1 s s s m n × + + ± -
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/22/2011 for the course EML 6653 taught by Professor Law during the Fall '09 term at University of South Florida - Tampa.

Page1 / 2

Came8pt30 - Q.8.30 Consider a steel rotating disk of hyperbolic cross-section with a = 0.125m b = 0.625 m t i = 0.125m t o = 0.0625m Determine the

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online