weakacidbaseeq

# weakacidbaseeq - A R COO H 2 O R COOH OH Water OH-H 3 O H 2...

This preview shows page 1. Sign up to view the full content.

Weak Acid/Weak Base Equilibrium Calculations Starting with an acid (proton donor) Starting with a base (proton acceptor) Fraction of charged conjugate H 2 O A N + + H 3 O + R COOH + H 2 O R COO - + H 3 O + = 10 ( pH - pK a ) Fraction of charged conjugate [A] [N] [A] [N] = [A] [N] + 1 P + H 2 O B + H 3 O + R NH 3 + + H 2 O R NH 2 + H 3 O + = [P] [B] [P] [B] + 1 K b [B] [OH - ] [P] = B P OH - H 2 O + + R NH 3 + H 2 O + R NH 2 OH - + N + H 2 O OH
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: -+ A R COO-+ H 2 O R COOH OH-+ Water OH-H 3 O + + H 2 O H 2 O + K w = 10-14 Conjugate acid/base pair K b K a = 10-14 [A] [N] = K b [OH-] K a = [N] [H 3 O + ] [A] K a = [B] [H 3 O + ] [P] = 10 pK a- pH ( ) [P] [B]...
View Full Document

## This note was uploaded on 11/27/2011 for the course CHM 365 taught by Professor Thomaszamis during the Spring '06 term at FSU.

Ask a homework question - tutors are online