ME211_sol4 - M62&quot; Hw4 \$361113&quot;. l. I 2*6-41)...

ME211_sol4
Download Document
Showing pages : 1 - 8 of 8
This preview has blurred sections. Sign up to view the full version!
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: M62" Hw4 \$361113". l. I 2*6-41) Locate the centroid of the shaded area bounded . by e parabola and the line y = a. - v or, ) n'cnrrrtzrrjflo't "4 #0:"? =fotly'i'7 =5(a7')= JA "Twig? if}; 09 "If ' -= 3di :: g3&quot;?- WA'IWFJTJKJ'MJ WWI??? 6-37 The shaft is supfnorted by a thrust bearing at A an a journal bearing at B, If L = 10 ft, the shaft will fail when the maximum moment is Mmax = 5 kip-ft. Determine the largest uniform distributed load w the 'shaft will support. ' _ A ' +TZF/59' '2',&quot; X'V50 \G'ZM:0 ':K+H)({ L tux&quot; vaA =%x~ z 2 - - w V 31w M) M" 7W 'K') ; &quot; I ~ 'v 39 Determline the rn'agnitude of the resultant force of 5; t 6 loading acting on the beam and specify where it acts 5 from point 0. W I 420 Ib/ft I l M =w06r = [\$(K-XJ'+/oo]a/;r Wk '35: FR iW =L'TSfX-s&gt;'+ Iva} c/x S \$[x-813 "WK!" 3 o = 1267 ( =13] Id? i=M:M : '(\$x3-8vx2+42m)o\$r L0" 125'! I967 f'd 200d; 3" [L of era/Mrth fa SeJhenf AC [FBD (9], we [we Va : '35'gl- A/lcw: MC mox'l &quot;4.29m = 0 Mt: - sd-H. Awbv 7": efng" of efm'MI/uh J'ejheaf D[ngm]' we Lave 1,21% =0 : A4,: 0 +155 =0: l/osoo=0. l/o=3oo( 9274,, = o = M 'Soonfo, The boom DF of the jib crane and the column D ave a uniform weight of 50 lb/ft. If the hoist and load weigh 300 1b, determine the normal force, shear force, and moment in the crane at sections passing through points A, B, and C. Prob. 7-12 Q Ma 5'50 uf-t 43:51:03 N320 =0: I/sS'fa'sov:0; Vgsgro [ 62MB =0; M5 '53'0X52{.3oax11=0; M5: LIFKHV 14:0 4.25:0: mM-'N-svv-lfma- M=Iloot 52M; = 0 = Me {toxAngxzs = a Me = 9125 l-H 6325 [4- ff -29 The semicircular arch is subjected to a uniform distributed load along its axis of wo per unit length. Determine the internal normal force, shear force, and Moment in the arch at 0 = 45. 9 nix =Wa((9)&amp; = rk/M'mw /9 : rev.) (1- M6) F 0 , 00 p7 : Lmdma = We (and) [a : mm; 9) Me, = fwaa 4/!) r = 13w, 5 All a: 4:0 a&quot; A 4;&quot; FIX: 0'2 72 Fx' ma, @544&quot;) -'-o zyzfm,z Ma. F . '- Fk -rw 5:?4 4 o , a" "rm 7 0 r ' 0797,14/0 Mn = 73mg 1'??? If L = 18 ft, the beam will fail when the maximum 5 r force is V&quot;lax = 800 lb, or the maximum moment is Mmax = 1200 lb - ft. Determine the largest intensity w of the distributed loading it will support. F" osst w + i : :-_&quot;'2&quot;z_ ts-.M :0 M : ' A HA ' 6A '2' L Vl'wc &quot; '2'; V .. l -114- w 2 gm (L/fz'. 1 2 MM - -14. x 6 -lzuo ; 416(8); X -wl&quot; Draw the shear and moment diagrams for the beam. 20 kip 20 kip 4 kip/ft 24 no k 39k First I: 15 ff 'er reach," Bowel on 34 = I23: zlx(90/zUo/'+4FX30) : 90 [&lt;71 20!: 4/". Fit. Ms M: C Irlrt M6 #20lequ o M Ma: 'kavf H 4%. wk E: IfH, (rH 8'1: U M+ 60x1" 20x50 40,"; 0 60k 30k W W- M Irf-c 51k. 4k Jolt 4xk 20k x "+t .; ' Iq 5'15. a,&quot; _ , , x 2M-0-4*3'*%Mwujnx:o 2': [.57 H. sha t. The support at A is a journal bearing and at B it is a thrust bearing. Draw the shear and moment diagrams for the ' me. jef 'l'le "Cf/n . 800 lb 1001b/in. kg/'H'dl '1y xma ~14....
View Full Document