ME211_sol4 - M62“ Hw4 $361113“. l. I 2*6-41) Locate the...

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Unformatted text preview: M62“ Hw4 $361113“. l. I 2*6-41) Locate the centroid of the shaded area bounded . by e parabola and the line y = a. - v or, ) n'cnrrrtzrrjflo't “4 #0:”? =fofitly’i’7 =5(§a7’)= JA “Twig? if}; 09 “If ‘ -= 3di :fi: g3"?- WA‘IWFJTJKJ’MJ WWI??? 6-37 The shaft is supfnorted by a thrust bearing at A an a journal bearing at B, If L = 10 ft, the shaft will fail when the maximum moment is Mmax = 5 kip-ft. Determine the largest uniform distributed load w the 'shaft will support. ‘— _ A —' +TZF/59‘ ‘2'," X'V50 \G‘ZM:0 ':—£K+H)({ L tux" vaA =%—x~ z 2 - - w V— 31w M) M“ 7W ’K’) ; " I ~ ‘v €39 Determline the rn'agnitude of the resultant force of 5; t 6 loading acting on the beam and specify where it acts 5 from point 0. W I 420 Ib/ft I l M =w06r = [$(K-XJ‘+/oo]a/;r Wk ‘35: FR iW =L'TSfX-s>‘+ Iva} c/x S $[x-813 “WK!” 3 o = 1267 (é =13] Id? i=M:M : £’°($x3-8—vx2+42m)o$r L0“ 125'! I967 f’dé 200d; 3” [L of era/Mrth fa SeJhenf AC [FBD (9], we [we Va : ’35’gl-é fiA/lcw: MC mox’l— "4.29m = 0 Mt: - sfld-H. Awbv 7“: effing” of efm'MI/uh fi J‘ejheaf €D[ngm]’ we Lave 1,21% =0 : A4,: 0 +155 =0: l/o—soo=0. l/o=3oo(£ 9274,, = o = —M» ’Soon—fo, The boom DF of the jib crane and the column D ave a uniform weight of 50 lb/ft. If the hoist and load weigh 300 1b, determine the normal force, shear force, and moment in the crane at sections passing through points A, B, and C. Prob. 7-12 Q Ma 5’50 uf-t 43:51:03 N320 =0: I/s—S‘fa’sov:0; Vgsgro [é 62MB =0; M5 ’53‘0X52{.3oax11=0; M5: LIFKHV 14:0 4.25:0: mM-‘N-svv-lfma- M=Ilooté 52M; = 0 = Me — {toxAngxzs = a Me = 9125 lé-H 6325 [4- ff -29 The semicircular arch is subjected to a uniform distributed load along its axis of wo per unit length. Determine the internal normal force, shear force, and Moment in the arch at 0 = 45°. 9 nix =£Wa(fl(9)fl&€ = rk/M'mw /9 : rev.) (1- M6) F 0 , 00 p7 : Lmfldflma = We (and) [a : mm; 9) Me, = fwaa 4/!) r = 13w, 5 All a: 4:0 a" A 4;" FIX: 0'2 72 Fflx’ ma, @544") -‘-o zyzfm,z Ma. F . ‘- Fk -—rw 5:?4 4 o , a” “firm 7 0 r ’ 0797,14/0 Mn» = 73mg 1‘??? If L = 18 ft, the beam will fail when the maximum 5 r force is V"lax = 800 lb, or the maximum moment is Mmax = 1200 lb - ft. Determine the largest intensity w of the distributed loading it will support. F” osst w + i : :-_"‘2"z_ fits-.M :0 M : 'flé— A HA ‘ 6A ‘2‘ — L Vl'wc " ’2';— V .. l -114- w 2 gm (L/fz‘. 1 2 MM - -14. x 6 -lzuo ; 416(8); X -wl" Draw the shear and moment diagrams for the beam. 20 kip 20 kip 4 kip/ft 24 no k 39k First I: 15 ff 'er reach,“ Bowel on 34 = I23: zlx(90/zUo/'+4FX30) : 90 [<71 20!: 4/”. Fit. Ms M: C Irlrt M6 #20lequ o M Ma: 'kavf H 4%. wk E: IfH, (rH 8'1: U M+ 60x1“ 20x50 40,“; 0 60k 30k W W- M Irf-c 51k. 4k Jolt 4xk 20k x “+t .—; §'§ Iq¥ 5‘15. a," _ , , x 2M-0-4*3'*%Mwuj—nx:o 2‘: [.57 H. sha t. The support at A is a journal bearing and at B it is a thrust bearing. Draw the shear and moment diagrams for the ' ® me. jef ‘l'le “Cf/n . 800 lb 1001b/in. kgfi/‘H‘dlé ‘1§y xma ~14.» ...
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