Me211_sol5

# Me211_sol5 - ME 2” Salim 5 *8-16. Two designs for a shock...

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Unformatted text preview: ME 2” Salim 5 *8-16. Two designs for a shock support are shown in the ﬁgure. The Spring has a stiffness of k = 15 kN/m and in (a) it is uncompressed, whereas in (b) it is originally stretched 0.2 m. Determine the average normal stress in the 5-mm-diameter bolt shank at A when the 6-kN load is applied. In (b) the bracket B is not connected to the support. 0’56 ‘1’)" 1% 61w .3 a “’"l/ \$1"ch F’kx; 6k/V=Url¢/t/h) x K: MW 2 0.2:“. WW é"! '3 614‘th mﬂnréd [J 0’:- i :. A £10m“: :3og/‘1Pa. ﬁ m]?”f,ﬂte *8-80. The built-up shaft consists of a pipe AB and solid rod BC. The pipe has an inner diameter of 20 mm and outer diameter of 28 mm. The rod has a diameter of 12 mm. Determine the normal stress at points D and E and represent the stress on a volume element located at each of these points. Prob. 8-80 ’ ABc :‘ \$0“ 7L , 7W” 3911.16 X!o"ln ‘ A“ : Edi—0H) = .3425, zo‘)x(a"t« 7? 4 FE 5 FD : Geri _ S’Xlol/l/ _ Au ’m-‘tz 4W4 (Wm - F9 4100’ G : -——- : /V __ D AA“ 30/. “((6141 ’ 5‘10”? ( feud/e) 1: 30L gx/o'g‘ ‘. 8-85. The lever is attached to the shaft A using a key that has a width of 8 mm and length of 25 m. If the shaft is fixed and a vertical force of 50 N is applied perpendicular to the handle, determine the average shear I. stress developed along section a—a of the key. ‘L ” 5w. +3244, : -—~450mm———i SON FxI; —§o x4“ :: 0 F: Koo/V :rw/V a 72".: #1:: L'é‘we/ é] Jim dim. 0t- ?” T = 0- N \$060.01; ’1 50“ Pa. 8-27. The bars of the truss each have a cr area of 1.25 in2. If the maximum average no any bar is not to exceed 20 ksi, determine th , . magnitude P of the loads that can be applied I’“* A ' 5' 3 as 4 r . 3 " +T2Fyzo- ’P*(f)FA5=o he , P FM; ’ I.“ 7P .1, y 2F.» * ﬁne + H51 Pt?) 2 o Fae = (-355 p *TEFYZO‘ F95 ' "75? ;0 F53 : 0.7517 Fm E + ’ twp F69 “>23 .0: map—559; W Jbl’la'f .5 " Fan-‘Z‘ilUP 3 Fe + (177/? “534 F c #5520: - i _ 4 _ f so 5% 2W7 P, 1.147;»?— _ m, Fee =5“? TL" 1‘71‘651‘ W364 heater is 30 O, , M1? 8‘ ’ (-1: z 1" P; *8-52. Th od cime ' b'e ed the ull f10 kN in a terfsiY): tesstrifg rIiaIr:h1isn:.l.1 Ii :hte altlgwablle noimal m stress for the wood is (0,)anow = 12 MPa and the allowable shear stress is Tallow = 1.2 MPa, determine the Aﬂowaéé 5/«ear 9kg“: {Age [in If I required dimensions b and t so that the specimen reaches V_ y I ' a 77'7". these stresses simultaneously. The specimen has a width 'W/V' of 25 mm. 1 Km!” r. 1 TlOkN A (.2 (/05) : toofwz) (aunt t: mam/(m MIN Allowaéé IVWMI 560'!" 72km?“ [ILvI'I‘afI-lh. 6%.. = if" (2.9(wé) : (0003) (0.0195 ...
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## This note was uploaded on 11/22/2011 for the course ME ME211 taught by Professor Barber during the Fall '10 term at University of Michigan.

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Me211_sol5 - ME 2” Salim 5 *8-16. Two designs for a shock...

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