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Unformatted text preview: Solution. We had the gradient < y x , ln x >, which at P (1 ,3) is <3 1 , ln 1 > = <3 , > . so the max rate of change is the length of the gradient, 3, which occurs in the direction ofv i = <1 , >, the direction of the gradient. Week 4 Homework: 14.7 max/min Problem 14.7.28: [omitted] We covered the Text Example 3, showing the use of the second deivative test. Week 8 Homework: 14.8 Lagrange multipliers We covered the text Example 2, which resembles the homework turnedin, using 2variable functions. For . . . an example in 3variables . . . [omitted]....
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This note was uploaded on 11/24/2011 for the course MATH 23 taught by Professor Yukich during the Spring '06 term at Lehigh University .
 Spring '06
 YUKICH
 Calculus, Chain Rule, Derivative, Integrals

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