21f08-31

# 21f08-31 - AFA8 Ù Ðe × Ó ÐÝÒÓÑ ia Ð×ÔÓÛ...

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Unformatted text preview: AFA8 Ù Ðe × Ó ÐÝÒÓÑ ia Ð×ÔÓÛ eÖ×aÒd Øh eeÜÔÓÒ eÒ Ø ia Ð Øi×Ò ØÒ ieØÓÓÒ ÐÝ Ðe ØÝÓÙÙ ×eØh ed eÒ iØ iÓÒ ØÓÒdd e Ö iÚa Ø iÚ e×h e Öea ÖeaÒÙÑ b e ÖÓ fgeÒ e Öa ÐÖÙ Ðe×Û h iha ÖeaÔÔ Ðied ØÓÒd Øh ed e Ö iÚa Ø iÚ e Ó faÒ e ÐeÑ eÒ Øa ÖÝ fÙÒ Ø iÓÒe Öe i×Øh eÖ×ØÓ fØh e×eÖÙ Ðe× : h eÓ ÖeÑ hedeÖ iÚa ØiÚeÓ faÓÒ × ØaÒ Øi× ( c ) ′ = 0 . D eeÔ Öe×Ù ÐØ h eÓ ÖeÑ F Ó ÖeahÔÓ × iØiÚe iÒ ØegeÖ n ( x n ) ′ = nx n − 1 . ÖÓÓ f F Ó Ö f ( x ) = x n f ′ ( x ) = lim h → f ( x + h )- f ( x ) h = lim h → ( x + h ) n- ( x ) n h = lim h → x n + n x n − 1 h + ··· + h n- x n h = lim h → n x n − 1 + ··· + h n − 1 = n x n − 1 . square h i×ÖÙ ÐeÛ Ó Ök ×fÓ Öa ÐÐÔÓÛ e Ö×Ó f x ÒÓ ØjÙ ×Ø iÒ Øege ÖÔÓÛ e Ö× Ðik eÛ eÔ ÖÓÚ edh e ÖeF Ó ÖeÜaÑ Ô ÐeÛ e ×aÛ b e fÓ ÖeØha Ø ( √ x ) ′ = 1 / (2 √ x ) Û h ih ØÖaÒ × Ða Øe×ØÓ ( x 1 / 2 ) ′ = (1 / 2) x ( 1 2 − 1 ) = 1 2 x − 1 2 , jÙ ×ØØØ iÒgØh e×aÑ eÖÙ Ðe h eÓ ÖeÑ [h eÔÓÛ eÖÖÙ Ðe ℄ F Ó ÖaÒ ÝÜedeÜÔÓÒ eÒ Ø a ( x a ) ′ = ax a − 1 ÓÒaÒ Ý iÒ ØeÖÚa ÐÓÒÛ h ih bÓ Øh x a aÒd x a − 1 a ÖebÓ ØhdeÒ ed h eÓ ÖeÑ 4 hedeÖ iÚa ØiÚeÓ fa×ÙÑ i× i×Øhe×ÙÑ...
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21f08-31 - AFA8 Ù Ðe × Ó ÐÝÒÓÑ ia Ð×ÔÓÛ...

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