lecnotes27 - MIT OpenCourseWare http:/ocw.mit.edu 5.111...

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MIT OpenCourseWare http://ocw.mit.edu 5.111 Principles of Chemical Science Fall 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms .
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27.1 5.111 Lecture 27 Transition Metals Topics: Formation of coordination complexes, coordination number, coordination complex notation, structures of coordination complexes, chelate effect, isomers, d- electron counting, and d-orbitals. Chapter 16 p. 669-681 (p. 620-631 in 3 rd ed). From Wednesday’s handout Now the answer to the biochemical question How is vitamin B 12 reduced in the body? Vitamin B 12 is reduced by a protein called flavodoxin. for vitamin B 12 is -0.526 V for flavodoxin is -0.230 V Is the reduction of vitamin B 12 by flavodoxin spontaneous? E °(cell) = E °(reduction) - E ° (oxidation) = (vitamin B 12 ) - (flavodoxin) = -0.526 V -(-0.230 V) = -0.296 V = -n E ° = -(1)(96485 Cmol -1 )(-0.296 V) = +28.6 kJ/mol Vitamin B 12 is a better reducing agent than flavodoxin. Vitamin B 12 should reduce flavodoxin not the other way around. So why don't we all have heart disease and megaloblastic anemia? Answer: S-adenosylmethionine provides the energy to drive the reaction. The G° for the cleavage of S-adenosylmethionine is -37.6 kJ/mol Today’s material Sc 21 V 23 Ti 22 Cr 24 Fe 26 Mn 25 Co 27 Cu 29 Ni 28 Zn 30 Y 39 Nb 41 Zr 40 Mo 42 Ru 44
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This note was uploaded on 11/27/2011 for the course CHEMICAL E 20.410j taught by Professor Rogerd.kamm during the Spring '03 term at MIT.

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lecnotes27 - MIT OpenCourseWare http:/ocw.mit.edu 5.111...

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