lecnotes30 - MIT OpenCourseWare http/ocw.mit.edu 5.111...

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MIT OpenCourseWare http://ocw.mit.edu 5.111 Principles of Chemical Science Fall 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms .
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30.1 5.111 Lecture Summary #30 Transition Metals Topic: Crystal Field Theory and the Spectrochemical Series. Chapter 16 A molecule’s color can depend on oxidation state or liganded state. Example: oscillating clock. Consider the overall reaction: - IO 3 + 2 H 2 O 2 + CH 2 (CO 2 H) 2 + H + ICH(CO 2 H) 2 + 2 O 2 + 3 H 2 O The overall reaction can be broken into two components ( 1 and 2 ), the second of which can be further divided into components ( a and b ): - (1) IO 3 + 2 H 2 O 2 + H + HOI + 2 O 2 + 2 H 2 O what is happening to “I”? (Note that the HOI produced in the first reaction is a reactant in the second reaction.) (2) HOI + CH 2 (CO 2 H) 2 ICH(CO 2 H) 2 + H 2 O (a) I - + HOI + H + I 2 + H 2 O what is being oxidized and what is being reduced in this reaction? ( b ) I 2 CH 2 (CO 2 H) 2 ICH 2 (CO 2 H) 2 + H + + I - As this reaction proceeds, the color will oscillate from clear to amber to deep blue. Specifically, I - is clear. The amber color is from I 2 formation. The deep blue color results from the I - and I 2 binding to the starch present in the solution. Thus, the color of iodine depends on its oxidation state and its liganded state (whether or not it is bound to starch). Transition metal coordination complexes
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lecnotes30 - MIT OpenCourseWare http/ocw.mit.edu 5.111...

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