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Unformatted text preview: 0.109249 I60 b ) Less than 700 mg P(X ≤ 700) = c ) Between 700 and 850 mg P(700 ≤ X ≤ 850) = P(X ≤ 850) f(P(X ≤ 700) =0.977750.371795=0.605955 P(700 ≤ X ≤850)= f(X≤850)f(X≤700) 5.3.6 , pg. 140, textbook . Given a normally distributed population with a mean of 100 and a standard deviation of 20 , find the following probabilities based on a sample of size 16 . _ ( a ) P(X ≥ 100) _ _ Solution. P(X ≥ µ) = 1 – f(X ≤ µ) = 1/2 general result _ __ µ x_mean = µ = 100 G58, σ x_mean = σ/√n = 20/√16 = 5 G59 _ X = 100 G57 _ _ P(X ≥ 100) = 1 – f(X ≤ 100) = 0.5 I60 _ ( b ) P(X ≤ 110) Solution: X= 110 G57 1 P(X≤110)= f(X≤110)=0.97725 I59 _ (c) P(96 ≤ X ≤ 108) I59 I59 P(96 ≤ X ≤ 108) =f (X≤108)f(X≤96)= 0.9452010.211855=0.733346 2...
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This note was uploaded on 11/24/2011 for the course MATH 3000 taught by Professor Kzaer during the Spring '05 term at St. Johns College MD.
 Spring '05
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