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# homework_1a - 1 st die Sum= 10(4,6(5,5(6,4 P(B)= 3/36= 1/12...

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St. John’s University Department of Mathematics and Computer Science Course MTH 1210 Homework #1a Feb 17’09 NAME___________________ PROBLEMS INVOLVING GENERAL DEFINITIONS AND LAWS OF PROBABILITY #1. One card is drawn from an ordinary deck of 52 cards. Find the probability of drawing the following cards. a. A 7 or 8 b. A black card or 5 c. A 7 or red 9 d. A red card or a non face card # 2 . Two dice are rolled. Find the probability of the following event: the first die is a number less than 5 or the sum is 10 . The probability of showing a number less then 5{1,2,3,4} by the first die(event A) is P(A)= 4/6 = 2/3. Let us find now the probability of rolling the sum of 10 (event B).

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Unformatted text preview: 1 st die Sum= 10 (4,6) (5,5) (6,4); P(B)= 3/36= 1/12 The probability of rolling the sum of 10 and showing a number less than 5 by the first die is P(A ∩ B) = 1/36 # 3 . Two dice are rolled. Find the probability of the following event: the first die is a number greater than 4 or the sum is multiple of 3 . ∑ = 3 (1,2) (2,1) ∑ = 6 (4,2) (3,3) (2,4) (1,5) (5,1) ∑ = 9 (3,6) (6,3) (5,4) (4.5) ∑ = 12 (6,6) Probability: 12/36 Greater then 4: 4/36 Show ALL your work for partial or full credit ....
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homework_1a - 1 st die Sum= 10(4,6(5,5(6,4 P(B)= 3/36= 1/12...

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