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Unformatted text preview: 1 st die Sum= 10 (4,6) (5,5) (6,4); P(B)= 3/36= 1/12 The probability of rolling the sum of 10 and showing a number less than 5 by the first die is P(A ∩ B) = 1/36 # 3 . Two dice are rolled. Find the probability of the following event: the first die is a number greater than 4 or the sum is multiple of 3 . ∑ = 3 (1,2) (2,1) ∑ = 6 (4,2) (3,3) (2,4) (1,5) (5,1) ∑ = 9 (3,6) (6,3) (5,4) (4.5) ∑ = 12 (6,6) Probability: 12/36 Greater then 4: 4/36 Show ALL your work for partial or full credit ....
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 Spring '05
 Kzaer
 Probability, Probability theory, Department of Mathematics and Computer Science

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