This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 1 st die Sum= 10 (4,6) (5,5) (6,4); P(B)= 3/36= 1/12 The probability of rolling the sum of 10 and showing a number less than 5 by the first die is P(A B) = 1/36 # 3 . Two dice are rolled. Find the probability of the following event: the first die is a number greater than 4 or the sum is multiple of 3 . = 3 (1,2) (2,1) = 6 (4,2) (3,3) (2,4) (1,5) (5,1) = 9 (3,6) (6,3) (5,4) (4.5) = 12 (6,6) Probability: 12/36 Greater then 4: 4/36 Show ALL your work for partial or full credit ....
View
Full
Document
 Spring '05
 Kzaer
 Probability

Click to edit the document details