{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

finalexam-sample-1 - max j H j j and use that to&nd the...

Info icon This preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
EEL 3123C TEST 3 - PART A - MANDATORY DURATION: 60 minutes Dec 7, 2007 1. The voltage across a 50 ° resistor is v ( t ) = 4 t exp ( ° j t j ) : What is the to- tal energy dissipated in the resistor? What percentage of the total energy dissipated in the resistor can be associated with the the frequency band 0 ± ! ± 10 rad/s? Hint: R cos 4 ° sin 2 °d° = 1 16 ° + 1 64 sin 2 ° ° 1 64 sin 4 ° ° 1 192 sin 6 ° (50) 2. Find the z parameters for the following circuit (30) 3. The following signals are sampled at 1KHz: (a) sin(100 ± t), and (b) exp(- 5t). Which ones would exhibit aliasing? Justify your answer. (20) EEL 3123C TEST 3 - PART B - OPTIONAL DURATION: 60 minutes 1. Compute the transfer function of a series RC low-pass °lter that has a load resistor R L in parallel with its capacitor.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: max j H ( j! ) j and use that to &nd the cut-o± frequency. (50) 2. For the circuit given below, there is no energy stored in the circuit at the time the switches close. Find the s-domain Thevenin equivalent of the circuit to the left of the terminals a,b. Use that to &nd an expression for i ( t ) for t ² + . (50) 1 2. z 11 = V 1 I 1 j I 2 =0 = (((60 + 20) jj 20) + 4) jj 80 = 16 z 22 = V 2 I 2 j I 1 =0 = (((80 + 4) jj 20) + 20) jj 60 = 22 : 56 z 12 = V 1 I 2 j I 1 =0 = ((80 + 4) jj 20) V 2 ((80 + 4) jj 20) + 20 80 (80 + 4) z 22 V 2 = 9 : 6& z 21 = V 2 I 1 j I 2 =0 = ((60 + 20) jj 20) V 1 ((60 + 20) jj 20) + 4 60 (60 + 20) z 11 V 1 = 9 : 6&...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern