sol_hm8_minggu - Solution of Hw 8 Ming Gu 8-2

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Solution of Hw 8 Ming Gu 8-2 API=(141.5/r)-131.5=(141.5/.875)-131.5=30.21 API 8-7 B0=227 res cc/ 167.4 ST cc=1.356 res bbl/STB Rs=((0.537+0.059) scf)/(167.44 ST cc * 6.2898e-6 bbl/cc)=565.9 scf/STB 8-10 1 1.1 1.2 1.3 1.4 1.5 1.6 0 1000 2000 3000 4000 5000 6000 Bo (bbl/STB) Reservoir Pressure (psi) Pb 0 100 200 300 400 500 600 700 800 900 1000 0 1000 2000 3000 4000 5000 6000 Rs(scf/STB) Pressure (psi) Pb Compared with the figures 8-1 and 8-2, they have the similar trends. 8-12 Bt=Bo+Bg(Rsb-Rs)=1.527+Bg*(941-941)=1.527 res bbl/STB 8-16 1 c o o T o B BP  = −   Assuming co is constant from 3500 to 4000 psi, we have
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