Exam 2 - View Attempt 1 of 1 Title: Started: Submitted:...

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View Attempt 1 of 1 Title: Exam 2 Started: March 30, 2011 9:50 AM Submitted: March 30, 2011 10:55 AM Time spent: 01:04:26 Total score: 17/20 = 85% Total score adjusted by 0.0 Maximum possible score: 20 1. The highly toxic substance, disulfur decafluoride, decomposes a S 2 F 10 <=> SF 4 + SF 6 In a study, S 2 F 10 was placed in a 2.0 L flask and heated to 100 [S 2 F 10 ] = 0.50 M. More S 2 F 10 was added and, when equilibrium [S 2 F 10 ] was 8.0 M. How did [SF 4 ] change from the original equ to the new one, after the addition of more S 2 F 10 ? Student Response A. new [SF 4 ] = 4 x old [SF 4 ] B. new [SF 4 ] = 16 x old [SF 4 ] C. Cannot be determined without knowing the value of K c . D. new [SF 4 ] = 1/16 x old [SF 4 ] E. new [SF 4 ] = 1/4 x old [SF 4 ] Score: 0/1 2. The nuclide 10 C undergoes spontaneous positron decay to maximum kinetic energy of the positron in MeV? (1 amu = 931 Note that masses (in amu) are: electron = 0.00054857990; proton = 1.00727647; neutron = 1.0 10 C = 10.016853 ; 10 B = 10.012937 . Student Response A. 0.00337
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B. 3.137 C. 0.0177 D. 3.648 E. 18658 Score: 0/1 3. Which of the following statements is true? Student Response A. An equilibrium constant expressed in terms of concentrations must be less than the corresponding equilibrium constant expressed in terms of pressure, regardless of the reaction. B. Catalysts effectively change the position of an equilibrium. C. The equilibrium constant may be expressed in terms of pressure or in terms of concentration for any reaction. D. the equilibrium concentrations are independent of the starting concentrations for a reaction E. When two opposing processes proceed at the same rate, the system is at equilibrium. Score:
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This note was uploaded on 11/25/2011 for the course CHEM 318 taught by Professor Rankin during the Spring '11 term at University of Texas at Austin.

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Exam 2 - View Attempt 1 of 1 Title: Started: Submitted:...

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