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Exam 3-1 (1)

# Exam 3-1 (1) - View Attempt 1 of 1 Title Exam 3 Started...

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View Attempt 1 of 1 Title: Exam 3 Started: August 7, 2008 8:13 AM Submitted: August 7, 2008 9:33 AM Time spent: 01:20:06 Total score: 15/20 = 75% Total score adjusted by 0.0 Maximum possible score: 20 1. What is the solubility in moles/liter for copper(II) sulfide at 25 o C given a K sp value of 2.0 x 10 -47 . Write using scientific notation and use 1 or 2 decimal places (even though this is strictly incorrect!) Student Response Valu e Correct Answer 1. 4.5E-24 100% Equals 4.47e-24 (100%) Equals 4.5e-24 (100%) General Feedback: K sp = S 2 Score: 1/1 2. At 25 o C the solubility of lead(II) sulfate is 1.26 x 10 -4 mol/L. Calculate the value of K sp at this temperature. Give your answer in scientific notation to 2 SIGNIFICANT FIGURES (even though this is strictly incorrect). Student Response Valu e Correct Answer 1. 1.6E-8 100% Equals 1.6e-8 (100%) General Feedback: K sp = S 2 Score: 1/1

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3. What is the solubility of silver chromate (K sp = 1.8 x 10 -12 ) in a solution of 0.15 M silver nitrate? Student Response Valu e Correct Answer Feedback a. 2.0 x 10 - 11 100% b. 7.7 x 10 -5 0% c. 1.2 x 10 - 11 0% d . 8.0 x 10 - 11 0% e. 1.3 x 10 -6 0% Score: 1/1 4. A precipitate of lead(II)chloride forms when 120.0 mg of NaCl is dissolved in 0.250 L of 0.12 M lead(II)nitrate. True or False? K sp of PbCl 2 is 1.7 x 10 -5 . Student Response Valu e Correct Answer Feedback 1 . True 0% 2. False 100% Score: 0/1 5.
A solution is 0.20 M HgNO 3 and 0.20 M Pb(NO 3 ) 2 . If solid Na 2 CO 3 is added to the solution, what is [Pb 2+ ] when Hg 2 CO 3 begins to precipitate?(K sp PbCO 3 = 7.4 x 10 -14 ; Hg 2 CO 3 = 8.9 x 10 -6 ) Student

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