Tutorial five solution 2011

# Tutorial five solution 2011 - Tutorial Five Solutions...

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1 Tutorial Five Solutions Q1 (0.5 point): Raman spectroscopy . Q2 (0.5 point): Fatigue stress is reduced near welded joints. X Q3 (2 points): The load will be shared equally, as top and bottom weld lengths are proportional to distance from the line of action of the load, i.e. aL 1 =bL 2 (load is not eccentric). Hence the load acts through the centroid of the weld group and does not twist the weld (in this case, there is no bending; the following equation can be directly used to calculate the shear stress). 1 2 P 25000 = 42.08969 42.1 (MPa) Ans. (L ) 2 (80 40)(7) 2 shear stress L t τ = = + + Q4 (3 points): Since aL 1 is not equal to bL 2 (load is eccentric and there is twisting on the weld). The weld centroid is now midway. The moment that twists the weld is: 25000( )(10 ) 250,000 twisting M N mm Nmm = = This moment will cause components of torsional shear at each end of the welds. The polar second moment of area of the welds is: 2 3 3 3 3 3 3 2 2 Ignore the t and t iterms. 50(60 2 )

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Tutorial five solution 2011 - Tutorial Five Solutions...

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