Tutorial 3 assignment TA

Tutorial 3 assignment TA - Biology 2C03 Genetics Tutorial 3...

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Biology 2C03: Genetics Tutorial 3 Assignment 1. The following data for the M-N blood types were observed from small villages in North and Central America. (group M=L M L M group MN = L M L N group N = L N L N ) (1 mark) Group Sample size M MN N Central America 170 106 56 8 North America 288 82 64 142 Calculate the frequencies of the L M and L N alleles for the two groups. Central America p = f(L M ) = (2nM + nMN) / 2n = (2*106 + 56) / 2*170 = 0.788 q= f(L N ) = 1 - 0.788 = 0.212 North America p = f(L M ) = (2nM + nMN) / 2n = (2*82 + 64) / 2*288 = 0.395 q= f(L N ) = 1 - 0.395 = 0.605 2. A population is composed of equal numbers of the genotype AA, Aa, and aa . The offspring produced by these genotypes number 996, 996, and 224 respectively. What are the relative fitness and the selection coefficient for each genotype? (1 mark) Fitnesses : W AA = 996/996 = 1 W Aa = 996/996 = 1 W aa = 224/996 = 0.225 Selection coeffiecients : s AA = 0 s Aa = 0 s aa = 0.775 3. You are studying a single-gene locus with two alleles in a population that is in Hardy-Weinberg equilibrium. Examination of a large sample of individuals from the population reveals there are six times

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This note was uploaded on 11/26/2011 for the course BIOLOGY 2c03 taught by Professor Dej during the Spring '11 term at McMaster University.

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Tutorial 3 assignment TA - Biology 2C03 Genetics Tutorial 3...

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