CH8-1 - A T G C A C T T A T G A 5’ 3’ sense anti-sense...

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Chapter 8 Part I Chapter 8 problems : 1-4, 6, 7, 11-13, 15, 18, 19, 23-27, 29, 31
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Gene Expression
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The Genetic Code 20 amino acids encoded for by 4 nucleotides By deduction: 1 nucleotide/amino acid = 4 1 = ____ combinations. 2 nucleotides/amino acid = 4 2 = ____ combinations. 3 nucleotides/amino acid = 4 3 = ____ combinations. …CATACTGAG… …His-Thr-Glu…
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The Genetic Code: Fig. 8.3
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…CATACTGAG… …His-Thr-Glu… Codons are __________________ A starting point is necessary to establish a ___________ The code is_______________, but ________________ The Genetic Code
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Mutations Frameshift insertion deletion Fig. 8.6
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Mutations Point mutations missense nonsense silent …TGGACTGAG… …Trp-Thr-Glu… …TGAACTGAG… …TGCACTGAG… …TGTACTGAG…
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Fig. 8.9 A closer look at gene expression
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Clicker: what would be the product of transcribing this gene? 1. ATGCACTTATGA 2. TACGTGAATACT 3. AUGCACUUAUGA 4. UACGUGAAUACU T A C G T G A A T A C T
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Unformatted text preview: A T G C A C T T A T G A 5’ 3’ sense anti-sense For example… T A C G T G A A T A C T A T G C A C T T A T G A 5’ 3’ 3’ 5’ sense anti-sense transcription translation Genetic code is almost universal All living organisms use same basic genetic code Translational systems can use mRNA from another organism to generate protein Rare cases where a codon specifies a codon different than the norm Prokaryotes Mitochondria Transcription Initiation Elongation Termination Promoter “___________” signify start of transcription Fig. 8.12 Initiation of transcription Fig. 8.11 a Promoter RNA polymerase (holoenzyme = core + sigma subunit) Direction of synthesis Terminator Elongation Fig. 8.11 b Transcription bubble Termination Fig. 8.11 c Terminator Intrinsic Extrinsic Hairpin loop...
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